Answer:
S'(-1, -2)
Explanation:
Coordinates of the vertices of the square PQRS have been given as P(2, 6), Q(6, 5), R(5, 1) and S(1, 2)
Rule to rotate a point by 180° about the origin,
(x, y) → (-x, -y)
By this rule new coordinates of the image will be,
P(2, 6) → P'(-2, -6)
Q(6, 5) → Q'(-6, -5)
R(5, 1) → R'(-5, -1)
S(1, 2) → S'(-1, -2)
Therefore, coordinates of S' will be (-1, -2).