Question

In a compound microscope, the objective has a focal length of 1.0 cm, the eyepiece has a focal length of 2.0 cm, and the tube length is 25 cm. What is the magnitude of the overall magnification of the microscope?

Answer 1

m = 312.5

Step-by-step explanation:

Given that,

The focal length of the objecive lens,
`f_o=1\ cm`

The focal length of eye piece,
`f_e=2\ cm`

length of the tube, L = 25 cm

We need to find the magnitude of the overall magnification of the microscope. It is given by the formula as follows :

`m=(L)/(f_o)* (D)/(f_e)`

D = 25 cm

So,

`m=(25)/(1)* (25)/(2)\\\\m=312.5`

So, the overall magnification of the microscope is 312.5.