Question

7. Eva bought popcorn, candy and a drink at

the movies. The popcorn was three times as
expensive as the candy and the drink was
twice as expensive as the candy. Eva spent a
total of $10.50.
a. Write an equation to represent the situation.
Let c represent the cost of the candy.
b. Find the value of c.
c. How much did Eva's
drink cost?

Answer 1

The equation to represent the situation is 3c + 2c + c = 10.50, where c represents the cost of the candy. The value of c is $1.75. The cost of Eva's drink is $3.50.

Step-by-step explanation:

a. The equation to represent the situation is 3c + 2c + c = 10.50, where c represents the cost of the candy. The 3c represents the cost of the popcorn, 2c represents the cost of the drink, and c represents the cost of the candy.

b. To find the value of c, we can simplify the equation: 6c = 10.50. Dividing both sides by 6 gives c = 1.75. Therefore, the cost of the candy is $1.75.

c. The cost of Eva's drink can be found by substituting the value of c into the equation. 2c = 2 * 1.75 = $3.50. Therefore, the drink cost $3.50.

Answer 2

Step-by-step explanation:

let $p, $c and $d represents the costs of popcorn, candy and a drink respectively. If the popcorn was three times as expensive as the candy then;

p = 3c.... 1

If the drink was twice as expensive as the candy then d = 2c .... 2

If Eva spent a total sum of $10.50 at the movies, the equation that represents the situation will be p + c + d = $10.50 .... 3

Substituting equation 1 and 2 into 3;

3c + c + 2c = $10.50

6c = $10.50

Hence the equation to represent the situation is 6c = $10.50 where c represents the cost of the candy.

b) To get c from the equation 6c = $10.50, we will simply divide both sides by the coefficient of c i.e 6 as shown

6c/6 = $10.50/6

c = $1.75

Hence the value of c is $1.75

c) The equation representing Eva's drink in terms of the candy is expressed as d = 2c

Substituting c = $1.75 into the equation will give;

d = 2(1.75)

d = 3.5

Hence the cost of Eva's drink is $3.50