Question

Ame

2. A train moving at 15 m/s slows down, and eventually stops after 5
seconds. What is the acceleration of the train?
G: Vi =
Vf=
U:
E: Formula
S: Substitute
S: Solve

Answer 1

Acceleration, a = -3 m/s²

Step-by-step explanation:

Given that,

Initial speed, u = 15 m/s

Final speed, v = 0

Time, t = 5 s

We need to find the acceleration of the train. It is equal to the change in velocity divided by time taken. So,

`a=(v-u)/(t)\\\\a=(0-15\ m/s)/(5\ s)\\\\a=-3\ m/s^2`

So, the acceleration of the train is 3 m/s² and it is deaccelerating.