Question

11. The second of two numbers is 5 more than twice the first. The sum of the numbers is 44. Find the numbers by writing and

solving a system of equations.
O A. (11, 33)
O B. (22, 22)
O C. (20, 24)
O D. (17, 22)
O E. (13,31)
O F. (17, 27)
explain too please

Answer 1

Answer: E. (13, 31)

Explanation:

Let x= first number

Let y= Second number

----------------------------------

y-5=2x

x+y=44

--------------------------------

y=2x+5

x+y=44

----------------------------

x+(2x+5)=44 ⇔ substitute y value in terms of x

x+2x+5=44

3x+5=44

3x=39

x=13

44-13=31

Hope this helps!! :)

Please let me know if you have any question or need further explanation

Answer 2

E

Explanation:

So the equation is y= 5+2x

and x+y=44

So we use the substitution method and says that y=44-x

So 44-x=5+2x

simplify

44-5=3x

x=13

there's only one option with x=13