Answer:
A
Explanation:
So we have the function:
![f(x)=y=\sqrt[3]{x-2}+8](https://img.qammunity.org/2021/formulas/mathematics/high-school/95fz75t5ct7dpt2d04mmrf8wejjspb37mp.png)
To find the inverse of the function, we can flip x and y and then solve for y. Therefore:
![x=\sqrt[3]{y-2}+8](https://img.qammunity.org/2021/formulas/mathematics/high-school/s8zmbcq73kbawqa6vl89f771cfj9k9ngg7.png)
Solve for y to find our inverse.
Subtract 8 from both sides:
![x-8=\sqrt[3]{y-2}](https://img.qammunity.org/2021/formulas/mathematics/high-school/3pv32vuq931cp101oarr4xfi5rggrcmzal.png)
Cube each side. The right cancels:
![(x-8)^3=y-2](https://img.qammunity.org/2021/formulas/mathematics/high-school/3ai0qto1xsktv4jci5tlmsz1nn57rh24if.png)
Add 2 to both sides:
![y=(x-8)^3+2](https://img.qammunity.org/2021/formulas/mathematics/high-school/q1lzt2jkpiwrotx7ambcj8jhplb69nhek7.png)
Therefore, our inverse is:
![f^(-1)(x)=(x-8)^3+2](https://img.qammunity.org/2021/formulas/mathematics/high-school/wlx573owpnjm4arxkc0mwo821809ci35u0.png)
The answer is A