Question

11. An AC waveform has a peak voltage of 50 VAC. What's the

waveform's RMS voltage?
O A. 50.0 VAC
B. 35.4 VAC
C. 24.8 VAC
O D.52.8 VAC

Answer 1

Option B - 35.4 VAC

Explanation:

Formula for peak voltage is;

V_p = V_rms × √2

Making V_rms the formula, we have;

V_rms = (V_p)/√2

We are given:Peak voltage: V_p = 50 VAC

Where 50 VAC means 50 Volts AC power

Thus;

V_rms = 50/√2

V_rms ≈ 35.4 VAC

So option B is correct