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An observer sits in a boat watching wave fronts move past the boat. The distance between successive wave crests is 0.80 m, and they are moving at 2.6 m/s.What is the wavelength of these waves? What is the frequency of these waves? What is the period of these waves?

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Answer:

The wavelength is
\lambda = 0.80 \ m

The frequency is
f = 3.25 \ Hz

Step-by-step explanation:

From the question we are told that

The distance between two successive crest is 0.80 m

The velocity is v = 2.6 m/s

Generally wavelength is the distance between two successive crest

So


\lambda = 0.80 \ m

Now the frequency is mathematically represented as


f = (v)/(\lambda )


f = (2.6)/(0.80 )


f = 3.25 \ Hz

User James Burns
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