Question

Given limit of f (x) = negative 4 as x approaches c and limit of g (x) = one-fifth as x approaches c. what is limit of left-bracket startfraction g (x) over f (x) endfraction right-bracket as x approaches c?

Answer 1

D. -1/20

Explanation:

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Answer 2

It looks like we're given

`\displaystyle \lim_(x\to c) f(x) = -4`

`\displaystyle \lim_(x\to c) g(x) = \frac15`

Since the limit of f(x) is finite and non-zero, we have by the quotient rule for limits

`\displaystyle \lim_(x\to c)(g(x))/(f(x)) = (\displaystyle \lim_(x\to c)g(x))/(\displaystyle \lim_(x\to c) f(x)) = (-4)/(\frac15) = \boxed{-20}`