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IF DE = 3x+8, EF = 4x+6, and DF = 28, find the value of x. [In your solution,

put x = YOUR ANSWER

IF DE = 3x+8, EF = 4x+6, and DF = 28, find the value of x. [In your solution, put-example-1

1 Answer

1 vote

Answer:

x = 2

Explanation:

Since, points D, E and F are collinear.

Therefore,

DF = DE + EF

28 = 3x + 8 + 4x + 6

28 = 7x + 14

28- 14 = 7x

14 = 7x


(14)/(7) = x \\ 2 = x \\ \huge \red { \boxed{x = 2}}

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