Question

Ind the value of the 60th term of the following sequence: 33, 28, 23, 18...

Answer 1

-262

Explanation:

Given sequence is: 33, 28, 23, 18...

First term a = 33

Common Difference d = 28 - 33 = - 5

To find:
`t_(60)`

By nth term of an AP.

`t_n = a + (n - 1)d \\ t_(60) = 33 + (60- 1)( - 5) \\ t_(60) = 33 + 59( - 5) \\ t_(60) = 33 - 295\\ t_(60) = - 262\\`