Question

two horses are pulling a 325 kg wagon, initially at rest. The horses exert 250 N and 178 N forward forces, respectively. Ignoring friction, how fast is the wagon moving 3.50 s later?

Answer 1

AFter 3.5 s, the wagon is moving at:
`4.62\,\,(m)/(s)`

Step-by-step explanation:

Let's start by finding first the net force on the wagon, and from there the wagon's acceleration (using Newton's 2nd Law):

Net force = 250 N + 178 N = 428 N

Therefore, the acceleration from Newton's 2nd Law is:

`F=m\,*\,a\\a = (F)/(m) \\a= (428)/(325)\, (m)/(s^2) \\a\approx 1.32 \,\,(m)/(s^2)`

So now we apply this acceleration to the kinematic expression for velocity in an object moving under constant acceleration:

`v_f=v_i+a\,*\,t\\v_f=0+1.32\,*\,3.5\,\,(m)/(s) \\v_f=4.62\,\,(m)/(s)`