Question

What is the power in a circuit that has a current of 12 A and a resistance of 100 Ω? (Note: 1 A2·Ω = 1 W) (1 point)

Answer 1

`\boxed{\sf Power \ in \ the \ circuit = 14.4 \ kW}`

Given:

Current (I) = 12 A

Resistance (R) = 100 Ω

To Find:

Power (P) in the circuit

Step-by-step explanation:

Formula:

`\boxed{ \bold{P = I^2 R}}`

Substituting value of I & R in the equation:

`\sf \implies P = {(12)}^(2) * 100 \\ \\ \sf \implies P = 144 * 100 \\ \\ \sf \implies P = 14400 \: A^2.\Omega \\ \\ \sf \implies P = 14400 \: W \\ \\ \sf \implies P = 14.4 \: kW`

`\therefore`

Power (P) in the circuit = 14.4 kW