Given :
Speed of bus for first 16 hours is , u = 15 km/h .
Distance he walked for next 0.4 hour is , v = 4.5 km/h .
To Find :
The average speed for the whole journey.
Solution :
Average speed is given by :
![v_(avg)=(u_1t_1+u_2t_2)/(t_1+t_2)\\\\v_(avg)=(15* 16 + 4.5* 0.4)/(16+0.4)\\\\v_(avg)=14.74\ km/h](https://img.qammunity.org/2021/formulas/physics/college/pnb8t6n5cmp7002v5vgc1k02hl1niqjs9i.png)
Therefore , the average speed of the journey is 14.74 km/h .
Hence , this is the required solution .