Question

Part 7: please assist me with these problems​

Answer 1

Answer: 10) 40° 11) 9.9

Explanation:

`\text{Law of Sines:}\quad (\sin A)/(a)=(\sin B)/(b)=(\sin C)/(c)`

10) Given: a = 31, b = 20, A = 84°

`(\sin 84^o)/(31)=(\sin B)/(20)\\\\\\(20\sin 84^o)/(31)=\sin B\\\\\\\sin^(-1)\bigg((20\sin 84^o)/(31)\bigg)=B\\\\\\39.9^o=B`

11) Given: a = 18, A = 105°, B = 32°

`(\sin 105^o)/(18)=(\sin 32^o)/(b)\\\\\\b=(18\sin 32^o)/(\sin 105^o)\\\\\\b=9.87`