Question

Please assist me with this problem: part 10​

Answer 1

c

Explanation:

Given

sinN =
`(a)/(b)` ( multiply both sides by b ) , then

a = bsinN → (a)

And

sinM =
`(a)/(y)` ( multiply both sides by y ), then

a = ysinM → (b)

Thus a is both (a) and (b)