Question

Simplify this expression.

(4y^2 - 13y + 3)/ (2y^2 - 5y - 12) • (2y^2 + 9y + 9)/ (16y^2 - 1) • (y^2 + 3y - 28)/ (y^2 - 9)

Answer 1

(y^2+3y-28)/(4y^2-15y-4)

Explanation:

(4y-1)(y-3)(2y+3)(y+3)(y+7)(y-3)/(2y+3)(y-4)(4y+1)(4y-1)(y-3)(y+3)

= (y+7)(y-3)/(y-4)(4y+1)

= (y^2+3y-28)/(4y^2-15y-4)

Answer 2

(y+7)/(4y+1).

Explanation:

If we factor all the polynomials we get:

(4y-1)(y-3) . (2y+3)(y+3) . (y-4)(y+7)

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(2y+3)(y-4) (4y-1)(4y+1) (y-3)(y+3)

we see that (4y-1), (y -3), (2y+3), (y+3) and (y - 4) are in the numerators and denominators so we can cancel them out.

This leaves us with:

(y + 7)

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(4y + 1)