Question

Let f(x)=x-3and h(x)=x2+6.what is (h⁰g)(1)​

Answer 1

The answer is 10 .

Explanation:

f(x) = x-3

h(x) =
`x^(2) +6`

Now ,

hog(1)

=h (1-3)

=h (-2)

=
`(-2)^(2)` +6

= 4+6

= 10