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x rays with wavelength of 2.0nm scatter from a nacl crystal with plane spacing 0.281 nm find the scattering

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Step-by-step explanation:

It is given that,

Wavelength of x-rays = 2 nm

Plane spacing, d = 0.281 nm

It is assumed to find the scattering angle for second order maxima.

For 2nd order, Bragg's law is given by :


2d\sin\theta=n\lambda

For second order, n = 2


\sin\theta=(n\lambda)/(2d)\\\\\sin\theta=(2* 2\ nm)/(2* 0.28\ nm)\\\\\theta=\sin^(-1)(7.14)

Here, θ is not defined. Also, the wavelength of x-rays is more than the plane spacing. It means that it cannot produce any diffraction maximum.

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