Question

Sapphire has an index of refraction of 1.77. The critical angle for sapphire in air with an index of refraction of 1.0 is _____ degrees.

Answer 1

The value is
`\theta = 34.40^o`

Step-by-step explanation:

From the question we are told that

The index of refraction is
`n_s = 1.77`

The refractive index of air is
`n_a = 1.0`

Generally the critical angle is mathematically represented as

`\theta = sin ^(-1) [(1)/(n_s) ]`

=>
`\theta = sin ^(-1) [(1)/(1.77) ]`

=>
`\theta = sin ^(-1) [0.565 ]`

=>
`\theta = 34.40^o`