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Please help!! Attachment below

Please help!! Attachment below-example-1
User BoomZilla
by
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1 Answer

4 votes

Answer:

hamburger =282 calories

soda=212 calories

Explanation:

2h+5c=1624 ...............×3

3h+2c=1270 ................×2

use eliminate method: multiply the first equation by 3, and second one by 2 to eliminate h first:

6h+15c= 4872

6h+4c=2540

subtract the two equations

6h+15c-6h-4c=4872-2540

11c=2332

c=2332/11

c=212 calories in soda

substitute c in any equation to get h

2h+5c=1624

2h+5(212)=1624

2h=1624-1060

2h=564

h=564/2=282

h=282 calories

check :

2(282)+5(212)=

564+1060=1624

3h+2c=1270

3(282)+2(212)=1270

User Michele Dorigatti
by
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