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Hello, please solve the following:

1.) y - x = 1
y + 4x =6 {SUBSITUTION METHOD}

2.) 2x + 3y = 3
3x - 6y = 15 {ELIMINATION METHOD}

1 Answer

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Answer:

1.) (1,2) 2.) (3,-1)

Step-by-step explanation:

1.) y - x = 1
y + 4x =6 {SUBSITUTION METHOD}
y - x = 1 , y = x + 1 | y - 1 = 1 --> y = 2
y + 4x = 6 --> (x + 1) + 4x =6 --> 5x + 1 =6 --> 5x =5 --> x=1

2.) 2x + 3y = 3
3x - 6y = 15 {ELIMINATION METHOD}

4x + 6y = 6 4(3) + 6y = 6
3x - 6y = 15 6y + 12 = 6

7x = 21 6y = -6

x = 3 y = -1

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