Question

How many lbs. of O2 are required to fully convert 1-lb of glucose (C6H12O6) to carbon dioxide and water

Answer 1

The correct answer is : 1.07 lbs

Step-by-step explanation:

solution:

molar mass glucose (C6H12O6) = 180 g/mol

molar mass of oxygen molecule (O2) = 32 g/mol (as we know molar mass of O = 16 g/mol)

the balanced reaction of conversion of water and oxygen to glucose is:

`C_(6)H_(12)O_(6) + 6O_(2) \rightarrow 6CO_(2) + 6H_(2)O ...(A)`

1 mol of C6H12O6 = 6 mol of O2 (from reaction A)

so, 180 g C6H12O6 = 192 g O2

that is, 0.396 lb of C6H12O6 = 0.423 lb of O2 ( 1 g = 0.00220462 lb )

so,

1 lb C6H12O6 =
`(1(lb) * 0.4233 (lb))/(0.3968 (lb))` = 1.07 lb O2

therefore, the correct answer is : 1.07 lbs