Question

The Bradenton Post polled 1,356 adults in the city to determine whether they wet their toothbrush before they put toothpaste on it. Of the respondents, 54% said they wet it first. Suppose 68% of all adults actually wet their toothbrush first. What are the mean and standard deviation of the sampling distribution?

Answer 1

deviation = -95.50147493 mean = 61

Explanation:

54% wet there brushes first

suppose 68% wet there brushes what is the mean

mean: a mean is where you add both numbers together to get a total then divide by how many numbers you added for now we wont need the amount of people we just need the percentages for this

54 + 68 = 122

we added to numbers so well divide by 2

122 divided by 2 or 122/2 is equal to 61

61 is our mean

standard deviation : this is were you take the known average 1356 adults and subtract the mean

1356- 61 = 1295 then divide by 1356 and times by 100

if the number is positive then the mean is higher than expected but luckily its a negative so its -95.50147493