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Find the value of the test statistic z using zequalsStartFraction ModifyingAbove p with caret minus p Over StartRoot StartFraction pq Over n EndFraction EndRoot EndFraction . Round to three decimal places. The claim is that the proportion of drowning deaths of children attributable to beaches is more than? 0.25, and the sample statistics include n equals 647 drowning deaths of children with? 30% of them attributable to beaches. A. 2.775 B. -2.937 C. 2.937 D. -2.775

User Yenshirak
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Answer:

C. 2.937

Explanation:

Given the following :

H0 : p = 0.25

H1 : p > 0.25

Number of observations (n) = 647

p' = 30% = 0.3

SD = sqrt[(p(1 - p) / n)]

1 - p = 1 - 0.25 = 0.75

SD = sqrt[(0.25 * 0.75) / 647]

SD = sqrt[0.0002897]

SD = 0.0170234

Z = (p' - p) / SD

Z = (0.3 - 0.25) / 0.0170234

Z = 0.05 / 0.0170234

Z = 2.9371187 = 2.937

User Muffel
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