Answer:
approximately 1.58 seconds
Explanation:
Set the function h(t)= -16t^2 + 40 = to 0 (the height above the ground when the ball hits). Then solve h(t)= -16t^2 + 40 = 0 for time (t):
-16t^2 + 40 = 0 becomes 16t^2 = 40. Solving for t^2: t^2 = 40/16 = 5/2.
Finally, we take the square root of this last result to determine t:
t = sqrt(10/4) = (1/2)sqrt(10)
The car hits the ground after (1/2)sqrt(10) seconds, or approximately 1.58 seconds.