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Solving these Quadratics for x using factoring 2x^2+5x = 3

User Zebi
by
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2 Answers

5 votes

Answer:

x = 1/2 ; x = -3

Explanation:

To solve this problem, we first need the quadratic to be set equal to x. Then, we can use factoring to solve for the values of x.

2x^2 + 5x = 3

2x^2 + 5x + -3 = 3 + -3

2x^2 + 5x + -3 = 0

Note that the first term's coefficient is 2. This factors into 1 and 2.

Note that the third term's coefficient is -3. This factors into 3 and -1.

From here, we will simply create the binomial factors for the quadratic.

(2x - 1) (x + 3) = 0

2x - 1 = 0 ; x + 3 = 0

2x - 1 + 1 = 0 + 1 ; x + 3 + -3 = 0 + -3

2x = 1 ; x = -3

2x * 1/2 = 1 * 1/2 ; x = -3

x = 1/2 ; x = -3

So our solutions for this quadratic equation are x = 1/2 or x = -3.

Cheers.

User Alexey Shein
by
3.8k points
2 votes

Solution:

2x²+5x=3

Using Factorisation method,

2x²+5x-3=0

2x²+6x-x-3=0

2x(x+3)-1(x+3)=0

(2x-1)(x+3)=0

2x-1=0 and x+3=0

x=1/2 and x=-3

User Sumitiscreative
by
4.1k points