Question

W7L5 Stoichiometry Practice 2

WESOME
1. N2 + 3H2 → 2 NH3
If 2.7 grams of NH3 are produced, how many moles of Nitrogen gas were
used?

Answer 1

.079 moles of Nirogen gas (N2)

Step-by-step explanation:

You can see from the equaton that each ONE mole of N2 produces TWO moles of NH3.

Find the number of moles of NH3 produced.

Using Periodic Table : Mole wt of NH3 = 17 gm/mole

2.7 gm / 17 gm/mole = .1588 moles

One half as many moles of N2 are needed = .079 moles