203k views
5 votes
How many solutions exist for the given equation?

12x + 1 = 3(4x + 1) - 2
zero
one
two
infinitely many

2 Answers

2 votes

Answer:


\Huge \boxed{\mathrm{infinite \ solutions}}

Explanation:


\sf 12x + 1 = 3(4x + 1) - 2

Using distributive property.


\sf 12x + 1 = 12x+3 - 2


\sf 12x + 1 = 12x+1

Subtracting 1 from both sides.


\sf 12x=12x

Dividing both sides by 12.


\sf x=x

All real numbers are solutions.

There are infinite solutions.

User Densil
by
5.2k points
2 votes

Answer:

infinitely many

Explanation:

12x + 1 = 3(4x + 1) - 2

Distribute

12x + 1 = 12x + 3 - 2

Combine like terms

12x+1 = 12x +1

Subtract 12x from each side

1 =1

Since this is always true, we have infinite solutions

User Kingbase
by
5.3k points
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