The question is incomplete; the complete question is;
What alkene would give the products below after reaction with O3, followed by reduction with (CH3)2S? Write the condensed structural formula (CH3)2C=O and CH3-CH2-CH=O
Answer:
2-methylpent-2-ene (C6H12)
Step-by-step explanation:
Ozonolysis is a wonderful method for determining the location of double bonds in an alkene since the oxygenated carbons in the carbonyl compounds formed after ozonolysis are the ones that were initially joined by the double bonds in the original alkene.
Hence if an alkene yields (CH3)2C=O and CH3-CH2-CH=O, the original alkene must be C6H12, that is, 2-methylpent-2-ene