Question

The radius of a nickel atom is 125 pm. How many nickel atoms would have to be laid side by side to span a distance of 1.74 mm

Answer 1

6960000 Nickel atoms

Step-by-step explanation:

radius = 125 pm = 125 x 10^-12 m

diameter of each atom = 125 pm x 2 = 250 pm = 250 x 10^-12 m

span of distance to be achieved = 1.74 mm = 1.74 x 10^-3 m

number of nickel atoms = (1.74 x 10^-3 m)/(250 x 10^-12 m) = 6960000 Nickel atoms