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John went on a bike ride to the store 4 miles away. If it took John 3 1/0 of an hour to get there and 12 of an hour to get back, what was his average rate of speed (miles per hour) for the entire trip?

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Answer:

His average rate of speed for the entire trip is 10 miles/hour.

Explanation:

We are given that John went on a bike ride to the store 4 miles away. If it took John 3/10 of an hour to get there and 1/2 of an hour to get back.

And we have to find his average rate of speed (miles per hour) for the entire trip.

As we know that the Distance-Speed-Time formula is given by;


\text{Speed}=\frac{\text{Distance}}{\text{Time}}

Here, the distance for the entire trip = 8 miles (4 miles for reaching store and 4 miles for returning back)

The time taken for the entire trip =
((3)/(10) ) of an hour to reach the store and
((1)/(2)) an hour to get back.

So, the average rate of speed for the entire trip =
\frac{\text{Total Distance}}{\text{Total Time}}

=
(8)/((3)/(10)+(1)/(2) )

=
(8)/((8)/(10) ) = 10 miles per hour

Hence, his average rate of speed for the entire trip is 10 miles/hour.

User Rocky Inde
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