Question

Calculate the molar concentration of HA (90.2 g/mol) in a solution that has a specific gravity of 1.24 and is 64% HNO3 (w/w).​

Answer 1

Step-by-step explanation:

Hello,

In this case, considering the given specific gravity we are to compute the density of the 64% HNO3 solution:

`\rho=1.24*1g/mL=1.24g/mL`

In such a way, since the given solution of nitric acid is 64 % by mass, we've got:

`(64gHNO_3)/(100g\ solution)`

Thus, by using the previously computed density and the molar mass of HA (90.2 g/mol) we can compute the required molar concentration as follows:

`M=((100g-64g)HA)/(100g\ solution)*(1.24g\ solution )/(1mL \ solution)*(1000mL\ solution)/(1L\ solution)*(1molHA)/(90.2gHA) \\\\M=4.95M`

Regards.