Answer:
There are a total of 720 chairs in the theater
Explanation:
First row = 20 chairs
Second row = 24 chairs
Third row = 28 chairs
The given is an arithmetic progression (A.P)
First term
a = 20
Common difference
d = 4
Number of terms
n=15
Sum of the chairs in the theater with a total of 15 rows
Sum of an A.P = n/2 { 2a + (n-1) d}
= 15/2{ 2*20 + (15-1) 4}
= 7.5 { 40 + (14) 4 }
= 7.5 { 40 + 56}
= 7.5(96)
=720 chairs