Question

A climber trekked to the top of Mount Everest, elevation 29,035 ft. From a starting point of 24976 ft. In a time of 15 hr, 35 min. Determine the average rate of climb in:(a) miles per minute

Answer 1

The average rate of climb in miles per minute is 8.2x10⁻⁴ miles/min.

Step-by-step explanation:

The average rate can be calculated as follows:

`\overline{v} = (y_(f) - y_(0))/(t_(f) - t_(0))`

Where:

`y_(0)`: is the initial height = 24976 ft

`y_(f)`: is the final height = 29035 ft

`t_(0)`: is the initial time = 0

`t_(f)`: is the final time = 15 hr, 35 min = 935 min

Then, the average rate of climb in miles per minute is:

`\overline{v} = (y_(f) - y_(0))/(t_(f) - t_(0))`

`\overline{v} = (29035 ft - 24976 ft)/(935 min - 0) = 4.34 (ft)/(min)*(1 mile)/(5280 ft) = 8.2 \cdot 10^(-4) miles/min`

Therefore, the average rate of climb in miles per minute is 8.2x10⁻⁴ miles/min.

I hope it helps you!