Question

What is the area of a rectangle that is \dfrac1{2} 2 1 ​ start fraction, 1, divided by, 2, end fraction of a meter long and \dfrac38 8 3 ​ start fraction, 3, divided by, 8, end fraction of a meter wide?

Answer 1

`Area = (3)/(16) m^2`

Explanation:

Given

Shape: Rectangle

`Length = (1)/(2)\ m`

`Width = (3)/(8)\ m`

Required

Determine the area of the rectangle;

Area is calculated as thus;

`Area = Length * Width`

Substitute values for Length and Width

`Area = (1)/(2) * (3)/(8)`

`Area = (1 * 3)/(2 * 8)`

`Area = (3)/(16)`

Hence, the area of the rectangle is
`(3)/(16)m^2`