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The pizza has an area of 78.5 in². What is the minimum width of a placemat that can be placed underneath it so that the pizza does not touch the table? Use 3.14 for pi.

User Frb
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1 Answer

5 votes

Answer:

10 in

Explanation:

This problem bothers on the mensuration of flat shapes, circles and square.

we know that the pizza has a circular profile

and the place-mat has a square profile.

Step one:

let us solve for the radius of the pizza


area-of- pizzza= \pi r^2\\\\ 78.5= 3.142*r^2\\\\r^2= 78.5/3.142\\\\r^2= 24.98\\\\r= √(24.98) \\\\r=4.998\\\\r= 5 in

Step two:

from inspection we know that the width of the place-mat is same as the diameter of the pizza

hence diameter of pizza

= 2r

=2*5

=10 in

User Munkey
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