56.8k views
0 votes
Find the point P that partitions the line segment AB given the ratio.

A (3, 6) B(4, 3) with the ratio 2:1

User Zygimantus
by
4.9k points

1 Answer

1 vote

Answer:


(11)/(3),4

Step-by-step explanation:

A line segment XY with points at X(
x_1,y_1) and Y(
x_2,y_2) divided by a point O(x, y) in the ratio n:m , the location of point O(x, y) is at:


x=(n)/(n+m)(x_2-x_1)+x_1\\ \\y=(n)/(n+m)(y_2-y_1)+y_1

Given line segment AB with location A (3, 6) B(4, 3), point P is given as:


x=(n)/(n+m)(x_2-x_1)+x_1=(2)/(2+1)(4-3)+3=(2)/(3)(1)+3=(11)/(3) \\ \\y=(n)/(n+m)(y_2-y_1)+y_1=(2)/(2+1)(3-6)+6=(2)/(3)(-3)+6=-2+6=4

The location of point P is at (
(11)/(3),4)

User Moritz Schmidt
by
4.8k points