Answer:
Step-by-step explanation:
since the object start its motion from rest and ends its motion at 300 m so
ΔS=S2-S1=300m-0m=300 m
given time is 22.4 sec therefore
v=ΔS/t
v=300/22.4=14.7 m/s
so the speed of the ball at the end of the track is 14.7 m/s
now to find the acceleration we know that
a=v/t
a=14.7/2.4
a=0.65m/sec²