Question

For what value of $a$ does the equation $3(2x-a) = 2(3x+12)$ have infinitely many solutions $x$?

Answer 1

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Explanation:

Answer 2

When a= -8, the equation 3(2x-a) = 2(3x+12) has infinitely many solutions

Explanation:

Given:

3(2x-a) = 2(3x+12)

6x - 3a = 6x + 24

Subtract 6x from both sides

6x - 3a - 6x = 6x + 24 - 6x

-3a = 24

Divide both sides by -3

a= 24 / -3

a = -8

Substitute a= -8 into the equation

3(2x-a) = 2(3x+12)

3{2x -(-8)} = 2(3x+12)

3(2x + 8) = 2(3x +12)

6x + 24 = 6x + 24

6x - 6x = 24 - 24

0 = 0

When a= -8, the equation 3(2x-a) = 2(3x+12) has infinitely many solutions