Answer:
a.
![T = 17s](https://img.qammunity.org/2021/formulas/mathematics/high-school/ognbdtc9r40slm1tay3yiqmsapsr0lz8jm.png)
b.
![D = 72cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/d07l9n77y6q5ixmuh9otpr9gkl47f3fn7o.png)
Explanation:
Given
Direct Variation
![Distance(D)\ \alpha\ Time (T)](https://img.qammunity.org/2021/formulas/mathematics/high-school/okl8hnw6vctxlifh8hw03k6krhf4c5ttgf.png)
D = 264 cm when T = 11 s
Calculating (a)
First, the constant of variation (k) as to be calculated;
Since, there exist a direct proportion; then,
![D\ \alpha\ T](https://img.qammunity.org/2021/formulas/mathematics/high-school/gl0lzepl5mfx27t5hje8qbs00c8uattsv7.png)
![D = kT](https://img.qammunity.org/2021/formulas/mathematics/high-school/qr338l9yd3sq1wulg4bx4ns83m3wwy41ld.png)
Make k the subject of formula
![k = (D)/(T)](https://img.qammunity.org/2021/formulas/mathematics/high-school/wplcm5n3lizwj2wkvzq1l7vb15j6iuya6b.png)
D = 264 cm when T = 11 s; So
![k = (264)/(11)](https://img.qammunity.org/2021/formulas/mathematics/high-school/d7dhj5ruqzbaxg7f47synwcjdem6ly0eat.png)
![k = 24](https://img.qammunity.org/2021/formulas/mathematics/college/akiqkqu4i5951mhum10mvyzza2xjme76e8.png)
So: Solving for (a)
![D = 408](https://img.qammunity.org/2021/formulas/mathematics/high-school/8f08exg364xwwhc1d54xzdpk45r6xqjjmg.png)
Substitute 408 for D and 24 for k in
![D = kT](https://img.qammunity.org/2021/formulas/mathematics/high-school/qr338l9yd3sq1wulg4bx4ns83m3wwy41ld.png)
![408 = 24 * T](https://img.qammunity.org/2021/formulas/mathematics/high-school/c8pw3oyes7m9olzj4mb32udtx27n8rbusk.png)
Divide both sides by 24
![(408)/(24) = T](https://img.qammunity.org/2021/formulas/mathematics/high-school/356gptr3va93g37mmdowz9058i39jo3ko3.png)
![T = (408)/(24)](https://img.qammunity.org/2021/formulas/mathematics/high-school/u6x8b72s0wy4a8oppebivx8vs931kw531q.png)
![T = 17s](https://img.qammunity.org/2021/formulas/mathematics/high-school/ognbdtc9r40slm1tay3yiqmsapsr0lz8jm.png)
Hence, time to move a distance of 408cm is 17s
Calculating (b)
![T = 3](https://img.qammunity.org/2021/formulas/mathematics/high-school/dlb34w9lhf9rk04npuufe26yg93ri67z51.png)
Substitute 3 for T and 24 for k in
![D = kT](https://img.qammunity.org/2021/formulas/mathematics/high-school/qr338l9yd3sq1wulg4bx4ns83m3wwy41ld.png)
![D = 24 * 3](https://img.qammunity.org/2021/formulas/mathematics/high-school/en98psqte7eujhkrckjrmg9kgqo40gmxtq.png)
![D = 72cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/d07l9n77y6q5ixmuh9otpr9gkl47f3fn7o.png)
Hence, distance covered in 3 seconds is 72cm