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A 0.140-kg baseball is dropped and reaches a speed of 1.20 m/s just before it hits the ground. It rebounds with a speed of 1.00 m/s. What is the change of the ball's momentum

User Nealmcb
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Final answer:

The change in momentum of the baseball, after it rebounds off the ground, is -0.308 kg.m/s, indicating a reversal in the direction of momentum.

Step-by-step explanation:

The question involves calculating the change in momentum of a baseball after bouncing off the ground. Momentum is defined as the product of an object's mass and velocity (p = m*velocity). When the baseball hits the ground and rebounds, there is a change in velocity, and hence a change in momentum.

Firstly, calculate the baseball's momentum just before impact: p before = 0.140 kg * 1.20 m/s = 0.168 kg.m/s. Then, calculate the momentum just after the rebound: p after = 0.140 kg * (-1.00 m/s) = -0.140 kg.m/s. The negative sign indicates the direction is opposite to the initial motion.

Next, find the change in momentum (∆p): ∆p = p after - p before = -0.140 kg.m/s - 0.168 kg.m/s = -0.308 kg.m/s. The change of momentum is a vector quantity, and in this context, the negative value indicates that the change is in the opposite direction of the initial momentum.

User Neverpanic
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