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What is the area of a square with the vertices (3, 3), (6, 6), (9,3), and (6,0)?

User Gorets
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1 Answer

2 votes

Answer:

A = 18 square units

Explanation:

taking A(3, 3), B(6, 6), C(9,3) and D(6,0)

we have:
y_A=y_C\quad and\quad x_B=x_D so the AC and BD are diagonals, that means:

AB = BC = CD = DA = s


s=√((6-3)^2+(6-3)^2)=√(3^2+3^2)=√(18)\\\\\\A=s^2=(√(18))^2=18

User Sam Tyson
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