Question

Please someone help me!!!!​

Answer 1

Answer:
`(\sqrt2)/(2)`

Explanation:

sin 75 = sin(30 + 45) = sin30 · cos45 + cos30 · sin45

`=(1)/(2)\cdot (\sqrt2)/(2)+(\sqrt3)/(2)\cdot(\sqrt2)/(2)\qquad =(\sqrt2+\sqrt6)/(4)`

sin 15 = sin(45 - 30) = sin45 · cos30 - cos45 · sin30

`=(\sqrt2)/(2)\cdot (\sqrt3)/(2)-(\sqrt2)/(2)\cdot(1)/(2)\qquad =(\sqrt6-\sqrt2)/(4)`

sin75 - sin15

`=(\sqrt2+\sqrt6)/(4)-(\sqrt6-\sqrt2)/(4)`

`=(\sqrt2+\sqrt6-\sqrt6+\sqrt2)/(4)\\\\=(2\sqrt2)/(4)\\\\=(\sqrt2)/(2)`