Answer:
- 0, 11, both multiplicity 2
- touch, not cross, at each 0
Explanation:
The function factors as ...
f(x) = x^4 -22x^3 +121x^2
f(x) = x^2(x^2 -22x +121)
f(x) = x^2(x -11)^2
The zeros are x=0 and x=11, each of multiplicity 2.
Because the multiplicity is even, the graph will touch at each zero, not cross.