Question

What is the kinetic energy of a 3000kg object moving at a velocity of 300m/s?

Answer 1

`\sf {\Large{ \purple{The \: kinetic \: energy \: of \: the \: object \: is \: 1.35 * {10}^(8)J }}}`

Step-by-step explanation:

`\textsf{ \underline{ \red{ \large{To find :-}}}}`

The kinetic energy of a moving object

`\textsf{ \underline{ \pink{ \large{Given :-}}}}`

Mass of the object (m) = 3000kg

velocity of the object (v) = 300m/s

`\textsf{ \huge{ \underline{ \underline{ \blue{Solution :-}}}}}`

`\sf Kinetic \: energy \: (K.E.) = (1)/(2) m {v}^(2) \\ \sf K.E. = (1)/(2) * 3000 * {300}^(2) \\ \sf K.E. = (1)/(2) * 3000 * 300 * 300 \\ \sf K.E. = 3000 * 300 * 150 \\ \sf K.E. = 135,000,000 \\ \textsf{(J = joule)} \\ \sf{ \green{ K.E. = 1.35 * {10}^(8)J }}`

Answer 2

• 135000000 Joules

Explanation:

Here we are given Mass of the object is 3000 kg and velocity is 300 m/s. and we need to calculate the Kinetic energy.

Formula of Kinetic energy is given by:

`\: \: \: \: \dashrightarrow \: \: \: { \underline{ \boxed{ \sf{KE = (1)/(2) mv^2 }}}}`

Where,

• m is mass
• v is velocity

On substituting the required values in above formula, we get:

`\\ \: \: \: \dashrightarrow \: \: \: \sf KE = (1)/(2) * 3000 * (300)^2 \\ \\ \\ \: \: \: \dashrightarrow \: \: \: \sf KE = (1)/(2) * 3000 * 90000 \\ \\ \\ \: \: \: \dashrightarrow \: \: \: \sf KE = \frac{1} {\cancel{{2}}} * { \cancel{3000}} * 90000 \\ \\ \\ \: \: \: \dashrightarrow \: \: \: \sf KE =1500 * 90000 \\ \\ \\ \: \: \: \dashrightarrow \: \: \: {\underline{\boxed{\sf{ KE =135000000 \: J}}}} \\ \\ \\`

• Kinetic energy is 135000000 Joules