Question

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Answer 1

Option (B)

Explanation:

`\begin{bmatrix}4 & 0\\ -1 & 2\\ -3 & -1\end{bmatrix}*\begin{bmatrix}0 & 1 \\ -3 & 1\end{bmatrix}`

In the multiplication of two matrices we multiply the column of 1st matrix with the row of the 2nd matrix and add them.

=
`\begin{bmatrix}(4* 0)+0(-3) &(4)1+0(1)\\ (-1)0+2(-3) &(-1)1+2(1)\\ (-3)0+(-1)(-3) &(-3)1+(-1)1 \end{bmatrix}`

=
`\begin{bmatrix}0 &4\\ -6 &1\\ 3 &-4 \end{bmatrix}`

Therefore, Option (B) will be the answer.