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3 votes
How many grams of a 14.0% (w/w) sugar solution contain 62.5
of sugar?

1 Answer

4 votes

Answer:


m_(solution)=446.4g

Step-by-step explanation:

Hello,

In this case, by-mass percent is computed in terms of the mass of the solute and the mass of the solvent as shown below:


\% m=(m_(solute))/(m_(solution)) *100\%

Thus, solving for the mass of the solution, we obtain:


(x)/(y) m_(solution)=(m_(solute))/(\% m)*100\%\\ \\m_(solution)=(62.5g)/(14.0\%)*100\% \\\\m_(solution)=446.4g

Regards.

User Dshkol
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