Question

A particle is thrown vertically upwards with velocity 20 metre per second find a the distance travelled by the particle in first 3 second and displacement of the particle in 3 seconds ​

Answer 1

Explanation:

`\huge\underline\bold\blue{ƛƝƧƜЄƦ}`

`\huge\underline\bold\green{Gïvëñ}`

[tex]\small\underline\bold\red{ v=0}[/tex]

`\</strong><strong>s</strong><strong>m</strong><strong>a</strong><strong>l</strong><strong>l</strong><strong>\underline\bold\blue{</strong><strong> </strong><strong>v</strong><strong> </strong><strong>=</strong><strong> </strong><strong>u</strong><strong>+</strong><strong>g</strong><strong>t</strong><strong>}`

`\</strong><strong>s</strong><strong>m</strong><strong>a</strong><strong>l</strong><strong>l</strong><strong>\underline\bold\blue{</strong><strong>0</strong><strong>=</strong><strong>2</strong><strong>0</strong><strong>-</strong><strong>1</strong><strong>0</strong><strong>t</strong><strong>}`

s = s(t=0 to 2 second) + s(2second to 3 second)

s = (ut+1\2(at)^2+ (ut+1\2at^2)

s = 20×2-1\2×10×4+1\2×10×1

s = 25

s = 20 - 5 = 15

Hope it helps