Answer:
23.28 g of O2.
Step-by-step explanation:
We'll begin by calculating the mass of hexane. This can obtain as follow:
Volume of hexane = 10 mL
Density of hexane = 0.66 g/mL
Mass of hexane =?
Density = mass /volume
0.66 = mass of hexane /10
Cross multiply
Mass of hexane = 0.66 x 10
Mass of hexane = 6.6 g
Next, we shall write the balanced equation for the reaction. This is given below:
2C6H14 + 19O2 —> 12CO2 + 14H2O
Next, we shall determine the masses of C6H14 and O2 that reacted from the balanced equation. This can be obtained as follow:
Molar mass of C6H14 = (12.01x6) + (1.008 x 14)
= 72.06 + 14.112
= 86.172 g/mol
Mass of C6H14 from the balanced equation = 2 x 86.172 = 172.344 g
Molar mass of O2 = 16x2 = 32 g/mol
Mass of O2 from the balanced equation = 19 x 32 = 608 g
From the balanced equation above,
172.344 g of C6H14 reacted with 608 g of O2.
Finally, we shall determine the mass of O2 needed to react with 10 mL (i.e 6.6 g) of hexane, C6H14. This can be obtained as follow:
From the balanced equation above,
172.344 g of C6H14 reacted with 608 g of O2.
Therefore, 6.6 g of C6H14 will react with = (6.6 x 608)/172.344 = 23.28 g of O2.
Therefore, 23.28 g of O2 is needed for the reaction.